(8x-2)^2+(3x-8)=(4x+13)

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Solution for (8x-2)^2+(3x-8)=(4x+13) equation: 



(8x-2)^2+(3x-8)=(4x+13)

We move all terms to the left:

(8x-2)^2+(3x-8)-((4x+13))=0

We get rid of parentheses

(8x-2)^2+3x-((4x+13))-8=0



We calculate terms in parentheses: -((4x+13)), so:

(4x+13)

We get rid of parentheses

4x+13

Back to the equation:

-(4x+13)



We add all the numbers together, and all the variables

3x+(8x-2)^2-(4x+13)-8=0

We get rid of parentheses

3x+(8x-2)^2-4x-13-8=0

We add all the numbers together, and all the variables

-1x+(8x-2)^2-21=0

We move all terms containing x to the left, all other terms to the right

-1x+(8x-2)^2=21

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